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Investigation Of Factors That Affect The Resistance

Of A Wire Essay, Research Paper


Introduction In this piece of coursework, I have been set the task of


investigating factors that affect the resistance of a wire. There are many


things that affect the resistance of a wire but I have only got the chance to


do one of these. The one I will choose will depend on it being the most


effective and on its ease to do. ???? Firstly, I will give an explanation of how


resistance works. Resistance is when travelling electrons in a wire collide with


the atoms of the wire. The collisions between the electrons and the atoms cause


the electrons to move slower, which in effect causes resistance. So, resistance


is how hard it is to move electrons through a wire. ???? Now, the factors that affect the resistance


of a wire are going to be described. ???? Firstly, temperature is a factor. If the


wire is heated, the atoms will move around more because there will be an


increase in energy. This would cause more collisions between the atoms and the


electrons. The increase in collisions would cause the resistance to rise. ???? This would be very hard to do, because the


equipment needed to do this experiment effectively has not been given to us. ???? Secondly, the width of the wire is a


factor. This will cause resistance to decrease


because of the increase in space in the wire. The increase in space means


that there is more space for the electrons to flow freely because there would


be fewer collisions with atoms. ???? I could do this by using different widths


of a wire; for example thin, medium, or thick copper could be used. ???? Thirdly, the material used would be a


factor. If the material being used contains atoms with a large number of


electrons on the outer shells, then this means there are more electrons


available. So, in theory, if the material has a large number of atoms, there


should be less resistance, because of the higher number of electrons .If the


atoms in the wire are closely packed, then this will cause an increase in resistance, due to frequent


collisions. ???? To do this I would use the same length and


width of many different wire materials, using the same amount of voltage each


time. ???? Finally, the length of the wire is a


factor. The longer the wire, the longer it will take electrons to get to the


end of the wire. This is because there will be more collisions between


electrons and atoms. So, in theory, the length of the wire should be directly


proportional to the resistance. ???? This would be very easy to do, and give


accurate results. Because of the length being proportional to the resistance, I


could link the length of a wire with the resistance of the wire, which would


make my graph more interesting. ???? Due to the effectiveness of this method, I


have decided to use the length of the wire as the factor that I am going to


use.Prediction I predict that, the longer the wire is, the more


resistance there will be due to more collisions between the electrons and


atoms. The length of the wire should be approximately proportionally the same


as the resistance. In theory, if the wire is doubled, then so will the


resistance. If the length is twice as much, then there will be twice as much


collisions, which would increase the resistance.Method Apparatus ·


Crocodile


clips ·


Ammeter ·


Voltmeter ·


Power


supply ·


Meter


ruler ·


Connecting


wires ·


sticky


tape ·


Thin


Constantine wire Diagram The reason I have chose to use Constantine wire is


because of its high resistance. This makes it a lot easier to record the


results, as it gives me higher numbers to work with. ???? The resistance


is going to be recorded

at nine different lengths. I have chosen to record the


results at this amount of lengths, as it will give me a much more accurate


result at the end of the experiment. ???? As you can see


in the diagram, I have chose to use a digital voltmeter instead of a


conventional analogue voltmeter, as this can give me a much more precise result


than an analogue meter. This is because the needle on an analogue meter could


be bent and give me the wrong reading, but a digital meter does not involve


needles, so would give a much clearer reading. ???? The way to


calculate the Resistance relies on this formula: ??????????????????????????????? Resistance =


Voltage/current I will use the Voltmeter provided to get the voltage, and


the ammeter provided to get the current (in amps).ResultsHere


is a result table from my main experiment:?????? 20 cm V I R 1 0.27 3.70 1.5 0.39 3.85 2 0.52 3.85 2.5 0.60 4.17 3 0.70 4.29 3.5 0.80 4.38 4 0.91 4.39 ?????? 30 cm V I R 1 0.17 5.88 1.5 0.25 6.00 2 0.33 6.06 2.5 0.41 6.09 3 0.48 6.25 3.5 0.55 6.36 4 0.71 6.67 ???? ? 40


cm V I R 1 0.14 7.14 1.5 0.21 7.14 2 0.28 7.14 2.5 0.34 7.35 3 0.40 7.50 3.5 0.46 7.61 4 0.52 7.69 ??? 50 cm V I R 1 0.11 9.09 1.5 0.16 9.38 2 0.21 9.52 2.5 0.25 10.00 3 0.29 10.34 3.5 0.33 10.61 4 0.37 10.82 ??? ??60 cm V I R 1 0.09 11.11 1.5 0.13 11.54 2 0.18 11.11 2.5 0.21 11.91 3 0.25 12.00 3.5 0.29 12.07 4 0.33 12.12 ????? 70 cm V I R 1 0.08 12.50 1.5 0.12 12.50 2 0.16 12.50 2.5 0.20 12.50 3 0.23 13.04 3.5 0.26 13.46 4 0.29 13.79 ???? ?80 cm V I R 1 0.07 14.29 1.5 0.10 15.00 2 0.13 15.38 2.5 0.16 15.63 3 0.19 15.79 3.5 0.22 15.91 4 0.26 16.00 ???? 90 cm V I R 1 0.06 16.67 1.5 0.09 16.67 2 0.12 16.67 2.5 0.14 17.86 3 0.16 18.75 3.5 0.18 19.44 4 0.20 20.00 ?? 100 cm V I R 1 0.05 20.00 1.5 0.07 21.43 2 0.09 22.22 2.5 0.11 22.73 3 0.13 23.08 3.5 0.15 23.33 4 0.17 23.52 Average resistance Length of wire (cm) Average resistance (ohms) 20 4.09 30 6.19 40 7.37 50 9.97 60 11.69 70 12.89 80 15.43 90 18.01 100 22.33 Conclusion In conclusion, I have found that my prediction was


correct. I said that the resistance will increase approximately proportionally


to the length, and as you can see from the graph, this was correct. This is


emphasised because the line of best fit is a straight line, which means the


resistance is proportional to the length. This proves the fact that the longer


the wire is, the more collisions there are between atoms and electrons. So if


the wire increases in length, so does the resistance. If the wire decreases in


length, so does the resistance. This can be shown in the diagram below:As you can see in the diagram, the wire on the top is


twice as big as the one below it, so it has twice the electrons too.EvaluationThis experiment has gone satisfactory, but there have


been certain things in the experiment that I have not been pleased with. ???? Some of my


results have turned out anomalous. This mainly being:60cm???????? ??????????????????? ?Anomalous V I R 1 0.09 11.11 1.5 0.13 11.54 2 0.18 11.11 2.5 0.21 11.91 3 0.25 12.00 3.5 0.29 12.07 4 0.33 12.12 I have probably ended up with this anomalous result


because of an error in recording my results. ???? However, as you


can see from my average resistance graph, the results are roughly on the same


line, so this anomalous result did not do much harm when the results are


averaged. ???? I have noticed,


now that I have finished my coursework, that there are a number of things I


could have done to get more accurate results. ???? Firstly, I


would do the experiment using the width and the material used as a factor too,


just to make sure that my averages are as correct as possible. ???? The next thing


I would have done is to use pointers instead of the crocodile clips which I


used. This is because pointers are a lot more accurate, because they have a


smaller surface area on their tips than crocodile clips. This in effect would


give much more accurate measurements.


381

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